13q^2=52

Solution for 13q^2=52 equation:

13q^2=52

We move all terms to the left:

13q^2-(52)=0

a = 13; b = 0; c = -52;
Δ = b2-4ac
Δ = 02-4·13·(-52)
Δ = 2704
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$q_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$q_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{2704}=52$
$q_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-52}{2*13}=\frac{-52}{26}
=-2
$
$q_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+52}{2*13}=\frac{52}{26}
=2
$